# Line slope calculator 3x+4y=16

**Straight line given by points A[0; 4] and B[4; 1]**

## Calculation:

**Slope-intercept form of line:**y = -0.75x+4

**Canonical form of the line equation:**3x+4y-16 = 0

**Parametric form of the line equation:**

x = 4t

y = -3t+4 ; t ∈ R

**Slope:**m = -0.75

**Slope angle of line: φ =**-36°52'12″ = -0.6435 rad

**X intercept:**x

_{0}= 5.3333

**Y intercept:**y

_{0}= q = 4

**Distance line from the origin:**d

_{0}= 3.2

**The length of the segment AB: |AB| =**5

**Vector: AB =**(4; -3)

**Normal vector: n =**(3; 4)

**Midpoint of the segment AB: M =**[2; 2.5]

**Perpendicular Bisector equation:**4x-3y-0.5 = 0

**Vector OA = (0; 4) ; |OA| = 4**

**Vector OB = (4; 1) ; |OB| = 4.1231**

**Scalar product OA .OB = 4**

**Angle ∠ AOB = 75°57'50″ = 1.3258 rad**